GO LANG - go routine cant print logs -> use chanel

 Go

ch := make(chan int) // Creates an unbuffered channel for integers

ch := make(chan string, 10) // Creates a buffered channel for strings with a capacity of 10

func main() {
// Unbuffered channel
unbufferedCh := make(chan int)

go func() {
fmt.Println("Sending 10 to unbuffered channel...")
unbufferedCh <- 10 // This will block until main receives
fmt.Println("Sent 10 to unbuffered channel.")
}()

fmt.Println("Receiving from unbuffered channel...")
val := <-unbufferedCh
fmt.Printf("Received %d from unbuffered channel.\n", val)

}

When a Go routine does not print expected logs, the primary reason is often that the main Go routine exits before the concurrently running Go routine has a chance to execute or complete its tasks, including printing.

            package main

            import "fmt"

            func main() {

            done := make(chan bool)

            go func() {

            fmt.Println("Hello from goroutine!")

            done <- true // Signal completion

            }()

            <-done // Wait for the signal

            fmt.Println("Main function done.")

            }